49x^2+56x-2009=0

Solution for 49x^2+56x-2009=0 equation:

49x^2+56x-2009=0

a = 49; b = 56; c = -2009;
Δ = b2-4ac
Δ = 562-4·49·(-2009)
Δ = 396900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{396900}=630$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-630}{2*49}=\frac{-686}{98}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+630}{2*49}=\frac{574}{98}
=5+6/7
$